CBSE CLASS 9TH SCIENCE(PHYSICS) CHAPTER MOTION (Graphical ) Part-2

CBSE CLASS 9TH SCIENCE(PHYSICS) CHAPTER MOTION (Graphical ) Part-2 


GRAPH:

A graph is a line, straight or curved which shows the variation of one quantity w.r.t other, which are interrelated with each other.
y=f(x)
In a relation of two quantities, the quantity which is made to alter at will, is called the independent variable.
The other quantity which varies as a result of this change is called the dependent variable. 
Graph Basic

Graph

In any graph , the independent variable is represented along x-axis (Time). 
Dependent variable is represented along y-axis (Distance, Displacement, Speed , Velocity, Acceleration etc).

TYPES OF GRAPHS:
1. When object is at Rest
2. When Object is in Uniform Motion
3. When Object is in Non Uniform Motion (Increasingly and decreasingly )

Types of Graphs in Motion
Types of Graphs in Motion

Distance-Time Graphs: 

Distance time graph denoted by s-t graph shows the variation of distance covered by object taken on dependent axis with time independent axis. 
Slope of the distance-time graph represents speed.
1).Distance time graph for a stationary object:
The distance time graph for a object at rest is straight line parallel to time axis.
Distance Time Graph When Object is at rest
Distance Time Graph When Object is at rest
2. Distance Time graph for Linear Uniform Motion:
For uniform motion along a straight line , the distance time graph is straight line inclined at angle with time axis.
Graph between Distance Time for Linear Uniform Motion
Graph between Distance Time for Linear Uniform Motion

3. Distance Time graph for Non Uniform Motion:
For graph with increasing slope with time represents speeding up. 

The graph with decreasing slope represents slowing down.

4. Distance Time graph which are not possible:
Distance Time Graph which are not possible
Distance Time Graph which are not possible



DISPLACEMENT TIME GRAPHS:
Displacement time graph denoted by s-t graph shows the variation of displacement covered by object taken on dependent axis with time independent axis. 

Slope of the displacement-time graph represents velocity.
Displacement Time Graph
Displacement Time Graph
VELOCITY-TIME GRAPHS:


ACCELERATION-TIME GRAPHS:


SLOPE OF DISTANCE TIME GRAPH:

slope of distance time graph
Slope of Distance time graph



Slope = Uniform speed = Distance travelled / time taken = Δx/Δt= x2 – x1 /t2 – t1  = (6-4)/ (6-4)= 1 m/s.

SLOPE OF VELOCITY TIME GRAPH:



Slope of velocity time graph

Slope = Uniform acceleration = velocity travelled / time taken = Δv/Δt= v2 – v1 /t2 – t = (6-4)/ (6-4)= 1 m/s2.

AREA UNDER VELOCITY - TIME GRAPH:

1)AREA UNDER CONSTANT VELOCITY - TIME GRAPH:

DISTANCE COVERED BY OBJECT IS GIVEN BY AREA UNDER THE GRAPH AS SHOWN BELOW:
AREA UNDER GRAPH OF CONSTANT VELOCITY
2) AREA UNDER LINEAR VELOCITY- TIME GRAPH :
DISTANCE COVERED BY OBJECT IS GIVEN BY AREA UNDER THE GRAPH AS SHOWN BELOW:

AREA UNDER LINEAR VELOCITY TIME GRAPH

EQUATIONS OF MOTION:

For uniformly accelerated linear motion of an object velocity ,acceleration and the distance covered in a given time interval are correlated by set of three equations known as equations of motion.
1. VELOCITY - TIME EQUATION : v = u + at
2. POSITION - TIME EQUATION : S = ut + 1/2at2.
3. POSITION - VELOCITY EQUATION : vu= 2aS
1. DERIVATION OF VELOCITY - TIME EQUATION : v = u + at
Consider the velocity - time graph of an object that moves under uniform acceleration shown as
Graph Velocity-Time Relation
Slope = Acceleration (a) = BD/AD 
a = (BC-DC)/OC = (v-u)/t
a =(v-u)/t
at=(v-u)
v = u + at

2. POSITION - TIME EQUATION : S = ut + 1/2at2.

Consider the velocity - time graph of an object that moves under uniform acceleration shown as
Velocity Time Graph

Distance covered by object = S = Area under graph
S = Area of trapezium OABDC 
S = 1/2 (sum of parallel side ) x perpendicular distance between parallel sides
S = 1/2 ( OA + BC ) x AD = 1/2 ( OA + BC ) x OC
S = 1/2 ( u + v ) x t          ( using v = u + at )
S = 1/2 ( u + u + at ) x t = 1/2 ( 2u + at ) x t
S = ( u + 1/2 at ) t = ut + 1/2at2

3. POSITION - VELOCITY EQUATION : vu= 2aS
Consider the velocity - time graph of an object that moves under uniform acceleration shown as

Distance covered by object = S = Area under graph
S = Area of trapezium OABDC 
S = 1/2 (sum of parallel side ) x perpendicular distance between parallel sides
S = 1/2 ( OA + BC ) x AD = 1/2 ( OA + BC ) x OC
S = 1/2 ( u + v ) x t       (using  t = ( v - u )/a )
S = 1/2 ( u + v ) ( v - u )/a
2aS = (v + u ) ( v - u )
2aS = vu
vu= 2aS

Comments

Post a Comment

Popular posts from this blog

CLASS 12TH PHYSICS EXPERIMENT To find the value of v for different values of u in case of a concave mirror and to find the focal length.

CBSE CLASS X SCIENCE CHAPTER ELECTRICITY LESSON PLAN 1

Branches of Science